<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: GED Math: Algebra</title>
	<atom:link href="http://www.passged.com/student_blogs/curtis/2009/01/22/ged-math-algebra/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.passged.com/student_blogs/curtis/2009/01/22/ged-math-algebra/</link>
	<description>My Fast and Smart Road to the GED</description>
	<lastBuildDate>Fri, 12 Mar 2010 17:41:14 +0000</lastBuildDate>
	<generator>http://wordpress.org/?v=2.9.2</generator>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
		<item>
		<title>By: Curtis</title>
		<link>http://www.passged.com/student_blogs/curtis/2009/01/22/ged-math-algebra/comment-page-1/#comment-1538</link>
		<dc:creator>Curtis</dc:creator>
		<pubDate>Thu, 02 Apr 2009 16:28:50 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/?p=74#comment-1538</guid>
		<description>Algebra&#039;s like a puzzle. Know those puzzles where you gotta move the pieces around to make a picture? It&#039;s like that. You gotta move the numbers around, so that &quot;x&quot; is by itself on one side. And there&#039;s rules.

Here&#039;s the key: you have to do the same thing to both sides of the equation.

So, if x + 3 = 5 and you want x by itself, you&#039;ve got to &quot;zero out&quot; the + 3. To make the + 3 cancel out, you&#039;ve got to subtract 3. That means you&#039;ll have 3 - 3 = 0 on the side with the x, and 0 is nothing.

But, if you want to subtract 3 from the left side, you gotta subtract 3 from the right, too, to keep &#039;em equal.

x + 3 - 3 = 5 - 3
x + 0 = 2
x = 2

Okay, that&#039;s the easy part. Hard part is, if you got x&#039;s on both sides.

2x = x + 5

What do I want to do? Subtract x from both sides, to get rid of the x on the right (x - x is the same as 3 - 3 or 23 - 23.... it&#039;s zero).

2x - x = x - x + 5
2x - x = 5

Now, what&#039;s 2x - x? The shorthand rule is, you subtract (or add) the numbers by the x&#039;s, and leave the x alone. &quot;x&quot; without a number has an invisible &quot;1&quot; next to it. So:
5x - 3x = 2x
22x + 5x = 7x
x + x = 2x
5x - x = 4x

That means, if 2x - x = 5, then x = 5.

Here&#039;s why. 5x means 5 times x. And 5 times x means x + x + x + x + x. That&#039;s what multiplication is, a shorthand way to add a number plus itself a bunch of time. 
5 x 9 = 9 + 9 + 9 + 9 + 9
5x = x + x + x + x + x

So, 2x - x means x + x - x. Two of the x&#039;s cancel out. 2 x&#039;s minus 1 x is... 1 x. Just like if you got 2 apples and take away 1 apple.

So... 5x + 14 = 3x + 22
I can subtract 14 from both sides to move all the numbers to the right...
5x = 3x + 8

Now, I can subtract 3x from both sides...
2x = 8

The last step, since x is multiplied by 2, is divide both sides by 2 to get the x by itself....

x = 4

There ya go!</description>
		<content:encoded><![CDATA[<p>Algebra&#8217;s like a puzzle. Know those puzzles where you gotta move the pieces around to make a picture? It&#8217;s like that. You gotta move the numbers around, so that &#8220;x&#8221; is by itself on one side. And there&#8217;s rules.</p>
<p>Here&#8217;s the key: you have to do the same thing to both sides of the equation.</p>
<p>So, if x + 3 = 5 and you want x by itself, you&#8217;ve got to &#8220;zero out&#8221; the + 3. To make the + 3 cancel out, you&#8217;ve got to subtract 3. That means you&#8217;ll have 3 &#8211; 3 = 0 on the side with the x, and 0 is nothing.</p>
<p>But, if you want to subtract 3 from the left side, you gotta subtract 3 from the right, too, to keep &#8216;em equal.</p>
<p>x + 3 &#8211; 3 = 5 &#8211; 3<br />
x + 0 = 2<br />
x = 2</p>
<p>Okay, that&#8217;s the easy part. Hard part is, if you got x&#8217;s on both sides.</p>
<p>2x = x + 5</p>
<p>What do I want to do? Subtract x from both sides, to get rid of the x on the right (x &#8211; x is the same as 3 &#8211; 3 or 23 &#8211; 23&#8230;. it&#8217;s zero).</p>
<p>2x &#8211; x = x &#8211; x + 5<br />
2x &#8211; x = 5</p>
<p>Now, what&#8217;s 2x &#8211; x? The shorthand rule is, you subtract (or add) the numbers by the x&#8217;s, and leave the x alone. &#8220;x&#8221; without a number has an invisible &#8220;1&#8243; next to it. So:<br />
5x &#8211; 3x = 2x<br />
22x + 5x = 7x<br />
x + x = 2x<br />
5x &#8211; x = 4x</p>
<p>That means, if 2x &#8211; x = 5, then x = 5.</p>
<p>Here&#8217;s why. 5x means 5 times x. And 5 times x means x + x + x + x + x. That&#8217;s what multiplication is, a shorthand way to add a number plus itself a bunch of time.<br />
5 x 9 = 9 + 9 + 9 + 9 + 9<br />
5x = x + x + x + x + x</p>
<p>So, 2x &#8211; x means x + x &#8211; x. Two of the x&#8217;s cancel out. 2 x&#8217;s minus 1 x is&#8230; 1 x. Just like if you got 2 apples and take away 1 apple.</p>
<p>So&#8230; 5x + 14 = 3x + 22<br />
I can subtract 14 from both sides to move all the numbers to the right&#8230;<br />
5x = 3x + 8</p>
<p>Now, I can subtract 3x from both sides&#8230;<br />
2x = 8</p>
<p>The last step, since x is multiplied by 2, is divide both sides by 2 to get the x by itself&#8230;.</p>
<p>x = 4</p>
<p>There ya go!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: worrie</title>
		<link>http://www.passged.com/student_blogs/curtis/2009/01/22/ged-math-algebra/comment-page-1/#comment-1528</link>
		<dc:creator>worrie</dc:creator>
		<pubDate>Sat, 28 Mar 2009 02:49:11 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/?p=74#comment-1528</guid>
		<description>just don&#039;t get it</description>
		<content:encoded><![CDATA[<p>just don&#8217;t get it</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Zaher</title>
		<link>http://www.passged.com/student_blogs/curtis/2009/01/22/ged-math-algebra/comment-page-1/#comment-1187</link>
		<dc:creator>Zaher</dc:creator>
		<pubDate>Sun, 25 Jan 2009 18:58:29 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/?p=74#comment-1187</guid>
		<description>This is very tough bro ! LOL !</description>
		<content:encoded><![CDATA[<p>This is very tough bro ! LOL !</p>
]]></content:encoded>
	</item>
</channel>
</rss>
