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	<title>Comments on: GED Math: Making a Problem into a Formula</title>
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	<link>http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/</link>
	<description>My Fast and Smart Road to the GED</description>
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		<title>By: Curtis</title>
		<link>http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/comment-page-1/#comment-1268</link>
		<dc:creator>Curtis</dc:creator>
		<pubDate>Thu, 05 Feb 2009 16:24:30 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/#comment-1268</guid>
		<description>Hey, yeah. You got your basic area problem, right? But you got a few bumps in the road. First, you got dimensions in feet, an&#039; you want an answer in yards. I recommend always changin&#039; everything to the dimensions you want in yo&#039; answer first off. That means, changin&#039; all the feet to yards. Now, there&#039;s three feet in a yard, and dat&#039;s jus&#039; somethin&#039; you got to know. So, to change feet into yards, divide by 3.

24 feet = 8 yards
18 feet = 6 yards
9 feet = 3 yards

Hey, you gotta know you&#039;re on the right track when all the numbers divide out evenly! Too bad real life don&#039;t work dat way. &#039;k. So&#039;s, now it&#039;s important to picture what the question&#039;s about, specially with this kinda dimension question. You got a room, 8 yards by 6 yards, and 3 yards tall. What&#039;s the area of the 4 walls? That&#039;s the real question... a wallpaper or carpet or tile (or anything that goes on a flat surface) question is an area question.

So... each wall got the same height, the height of the room...3 yards (9 feet):

wall 1: 3 yards x ?
wall 2: 3 yards x ?
wall 3: 3 yards x ?
wall 4: 3 yards x ?

So, what&#039;s the width of the walls? well, 2 walls is 8 yards long (the two walls opposite of each other on the sides of the room that&#039;re 24 feet) and 2 walls is 6 yards long (the two walls opposite of each other on the sides of the room that&#039;re 18 feet).

wall 1: 3 yards x 8 yards
wall 2: 3 yards x 8 yards
wall 3: 3 yards x 6 yards
wall 4: 3 yards x 6 yards

To find the area, multiply:

wall 1: 3 yards x 8 yards = 24 square yards
wall 2: 3 yards x 8 yards = 24 square yards
wall 3: 3 yards x 6 yards = 18 square yards
wall 4: 3 yards x 6 yards = 18 square yards

And to find the total, add:

24 + 24 + 18 + 18 = 48 + 36 = 84 square yards

Answer&#039;s 84!

I&#039;m gonna move this to a blog post later, too, with a picture...cuz sketchin&#039; it out sure can help.

Curtis</description>
		<content:encoded><![CDATA[<p>Hey, yeah. You got your basic area problem, right? But you got a few bumps in the road. First, you got dimensions in feet, an&#8217; you want an answer in yards. I recommend always changin&#8217; everything to the dimensions you want in yo&#8217; answer first off. That means, changin&#8217; all the feet to yards. Now, there&#8217;s three feet in a yard, and dat&#8217;s jus&#8217; somethin&#8217; you got to know. So, to change feet into yards, divide by 3.</p>
<p>24 feet = 8 yards<br />
18 feet = 6 yards<br />
9 feet = 3 yards</p>
<p>Hey, you gotta know you&#8217;re on the right track when all the numbers divide out evenly! Too bad real life don&#8217;t work dat way. &#8216;k. So&#8217;s, now it&#8217;s important to picture what the question&#8217;s about, specially with this kinda dimension question. You got a room, 8 yards by 6 yards, and 3 yards tall. What&#8217;s the area of the 4 walls? That&#8217;s the real question&#8230; a wallpaper or carpet or tile (or anything that goes on a flat surface) question is an area question.</p>
<p>So&#8230; each wall got the same height, the height of the room&#8230;3 yards (9 feet):</p>
<p>wall 1: 3 yards x ?<br />
wall 2: 3 yards x ?<br />
wall 3: 3 yards x ?<br />
wall 4: 3 yards x ?</p>
<p>So, what&#8217;s the width of the walls? well, 2 walls is 8 yards long (the two walls opposite of each other on the sides of the room that&#8217;re 24 feet) and 2 walls is 6 yards long (the two walls opposite of each other on the sides of the room that&#8217;re 18 feet).</p>
<p>wall 1: 3 yards x 8 yards<br />
wall 2: 3 yards x 8 yards<br />
wall 3: 3 yards x 6 yards<br />
wall 4: 3 yards x 6 yards</p>
<p>To find the area, multiply:</p>
<p>wall 1: 3 yards x 8 yards = 24 square yards<br />
wall 2: 3 yards x 8 yards = 24 square yards<br />
wall 3: 3 yards x 6 yards = 18 square yards<br />
wall 4: 3 yards x 6 yards = 18 square yards</p>
<p>And to find the total, add:</p>
<p>24 + 24 + 18 + 18 = 48 + 36 = 84 square yards</p>
<p>Answer&#8217;s 84!</p>
<p>I&#8217;m gonna move this to a blog post later, too, with a picture&#8230;cuz sketchin&#8217; it out sure can help.</p>
<p>Curtis</p>
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	<item>
		<title>By: Zaher</title>
		<link>http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/comment-page-1/#comment-1266</link>
		<dc:creator>Zaher</dc:creator>
		<pubDate>Thu, 05 Feb 2009 09:10:32 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/#comment-1266</guid>
		<description>Hello , Curtis ,

Can you show me how you work with this one ?

A room is 24 feet long, 18 feet wide, and 9 feet high. How many square yards of wallpaper are needed to paper the four walls of the room?

Thanks ,

Zaher</description>
		<content:encoded><![CDATA[<p>Hello , Curtis ,</p>
<p>Can you show me how you work with this one ?</p>
<p>A room is 24 feet long, 18 feet wide, and 9 feet high. How many square yards of wallpaper are needed to paper the four walls of the room?</p>
<p>Thanks ,</p>
<p>Zaher</p>
]]></content:encoded>
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	<item>
		<title>By: Zaher</title>
		<link>http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/comment-page-1/#comment-1176</link>
		<dc:creator>Zaher</dc:creator>
		<pubDate>Mon, 19 Jan 2009 00:06:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/#comment-1176</guid>
		<description>Hello again , Curtis ! 

I came across another problem and can&#039;t figure out how to approach it . It is as follows :  

If x= y-3 and y=z^2, what is x in terms of z?

I think this involves the use of exponents stuff but I can&#039;t make it up to work for me  !

Let me know man ! 

Zaher</description>
		<content:encoded><![CDATA[<p>Hello again , Curtis ! </p>
<p>I came across another problem and can&#8217;t figure out how to approach it . It is as follows :  </p>
<p>If x= y-3 and y=z^2, what is x in terms of z?</p>
<p>I think this involves the use of exponents stuff but I can&#8217;t make it up to work for me  !</p>
<p>Let me know man ! </p>
<p>Zaher</p>
]]></content:encoded>
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		<title>By: ged math test : ged practice test : ged test : ged : ged study guide : ged test score : ged writing test</title>
		<link>http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/comment-page-1/#comment-103</link>
		<dc:creator>ged math test : ged practice test : ged test : ged : ged study guide : ged test score : ged writing test</dc:creator>
		<pubDate>Wed, 24 Sep 2008 14:56:10 +0000</pubDate>
		<guid isPermaLink="false">http://www.passged.com/student_blogs/curtis/2008/09/09/ged-math-making-a-problem-into-a-formula/#comment-103</guid>
		<description>[...] The GED tests your ability to understand math formulas by seeing if you can choose the right formula to represent a word problem. This week, Curtis walks you through a math formula question. [...]</description>
		<content:encoded><![CDATA[<p>[...] The GED tests your ability to understand math formulas by seeing if you can choose the right formula to represent a word problem. This week, Curtis walks you through a math formula question. [...]</p>
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